1/x-2+4/x+3=3/x^2+x-6

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Solution for 1/x-2+4/x+3=3/x^2+x-6 equation: 



1/x-2+4/x+3=3/x^2+x-6

We move all terms to the left:

1/x-2+4/x+3-(3/x^2+x-6)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2+x-6)!=0

x∈R



We add all the numbers together, and all the variables

1/x+4/x-(3/x^2+x-6)+1=0

We get rid of parentheses

1/x+4/x-3/x^2-x+6+1=0

We calculate fractions

We do not support expression: x^3

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